Maryland senior shortstop AJ Lee has been named Big Ten Player of the Week after a dominant four games. It is Lee’s first weekly conference honor of the season.

In one game against James Madison and three games against Iowa this week, Lee hit .588 (10-for-17) with three home runs, two doubles and six RBI. He also worked two walks, stole two bases and came in to score eight times in the four Maryland victories.

Lee homered in each of the first three games of the weekend, including the biggest home run of his career — a walk-off bomb against Iowa Thursday night.

The senior started his great week by snapping an 0-for-25 slump in Tuesday’s 6-5 win over James Madison, recording a hit in his final three at-bats. He singled in the sixth and seventh, and then hit what turned out to be a game-winning solo home run in the top of the ninth.

He followed that up with a 3-for-4 day in Thursday’s opener against the Hawkeyes. Before the walk-off long ball, he singled twice and put down an RBI sacrifice bunt.

On Friday against Iowa, Lee put together a 2-for-4 day. He singled in the fifth and then hit his third home run in as many games with a solo shot in the bottom of the eighth.

In Saturday’s regular season finale, Lee posted another 2-for-4. After reaching on errors in his first two at-bats, he doubled in the fourth and fifth innings. Then, in his final career plate appearance at Bob ‘Turtle’ Smith Stadium, Iowa showed Lee the ultimate form of respect, and sent him to first base on an intentional walk.

Lee and the Terps will now head to Omaha, Nebraska for the 2019 Big Ten Tournament, where they will play their opening game against Illinois at 10:00 a.m. ET on Wednesday. Pregame coverage will start at 9:30 a.m. with Zach Solon on the call live from TD Ameritrade Trade Park on the Maryland Baseball Network.